16^2+12^2+c^2=

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Solution for 16^2+12^2+c^2= equation: 



16^2+12^2+c^2=

We move all terms to the left:

16^2+12^2+c^2-()=0

We add all the numbers together, and all the variables

c^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{0}{2}=0$

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